Step 1: Find the mean
Step 2: Find the deviation from the mean
Step 3: Take the absolute value of the deviation
Step 4: Find the mean of the absolute deviation.
x----x-mean
63 63-63 0
69 69-63 6
62 62-63 -1
57 57-63 -6
64 64-63 1
mean = (63+69+62+57+64)/5 = 63
Taking the absolute deviations, we have 0,6,1,6,1
Averaging these deviations : (0+6+1+6+1)/5 =14/5 = 2.8
Mean absolute deviation = 2.8
57 questions right out of 62 is 91.94%.
For 54 60 62 52: σ=4.761
15.72683482 is the standard deviation for that set of numbers.
It is 53.66 recurring.
The answer is 57 , because the question is 62 = 1s +5 . I put a 1 in front of the s , because if there's a letter w/out a # in the front , there's an imaginary 1 in the front of that letter , & you minus 5 from positive 5, ( write that under the positive 5 ), then if you do something to one side , you do it to the other , so put minus 5 under 62 . , & you cross off positive 5 & negative 5 on the right side . & 62 - 5 = 57 . and bring down the equal sign , & 1s , & divide 1 from 1s , & 1 from 57 , & 57 divided by 1 is 57 . So the answer equals 57 . i Hope this helped you . (:
z = (x - mean_x)/standard_deviation → z = (62 - 57)/3.5 = 1.43 Looking up z = 1.43 in normal tables gives a value of 0.4236 which is the probability that the value lies between 57 and 60. The probability of getting between 57 and 62 mpg is approx 42.36 %
57 questions right out of 62 is 91.94%.
-36
For 54 60 62 52: σ=4.761
62
Square the standard deviation to obtain the variance. The variance is 62 or 36.
It is: 180-61-62 = 57 degrees
It is: 62+8-7-6 = 57
15.72683482 is the standard deviation for that set of numbers.
91.94%
It is 53.66 recurring.
3 times with remainder 5.