0
Add your answer:
Earn +20 pts
How do you factor x minus 1 cubed minus x plus 1 cubed?
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
What is 2x cubed minus 10x squared minus 12x?
2x(x−6)(x+1)
How do you factor variable cubed minus the variable?
x(x + 1)(x -1)
How can you get to the number two in a tricky way?
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
What is 4a cubed minus 4a squared?
4a3 - 4a2 = 4a2*(a - 1)
How do you factor x minus 1 cubed minus x plus 1 cubed?
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
How do you factor 8x cubed minus 1?
(2x - 1)(4x2 + 2x + 1)
What is 2x cubed minus 10x squared minus 12x?
2x(x−6)(x+1)
How do you factor x cubed minus 27?
t3-1/27
What is x minus 1 cubed?
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
How do you factor variable cubed minus the variable?
x(x + 1)(x -1)
How can you get to the number two in a tricky way?
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
x cubed minus x?
X cubed - X cubed is zero.
How do you factor 9x cubed plus 18x squared minus x minus 2?
(x + 2)(3x - 1)(3x + 1)
What is 4a cubed minus 4a squared?
4a3 - 4a2 = 4a2*(a - 1)
How do you factor 64 x cubed minus y cubed?
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
Factor x cubed minus one?
(x - 1)(x^2 + x + 1)
