for multipcation!
multipcation is used because its to find out how many things or objects you need if everyone gets a certain amount
20
since its not a prime number, there are a few. a way to figure one out is if you add up all the digits and the sum is divisible by 3, then the entire original number is divisible by 3. In this case: 3+1+5=9 9 is divisible bye 3 evenly, so 315 is divisible by 3. Now you have to figure out WHAT times 3 equals 315. the answer to this is 105.
Instead of having to do multiples of two numbers with several digits in each, all you need to be able to do is to multiply pairs of 1 digit numbers, add the correct number of 0s for powers of tens, and then add together a string of numbers. Actually, all that sounds a lot more complicated than it is. It may be easier to explain with an example: 567*89 Adding Partial products: (500*80 + 500*9 + 60*80 + 60*9 + 7*80 + 7*9) = 40000 + 4500 + 4800 + 540 + 560 + 63 = 50463
Product.
for multipcation!
1x9:9 3x3:9
1 and 67
It is 4 times the side length.
It enables the order of the multiplicands to be changed without affecting the result. Thus, A*B = B*A
52 = 1 x 52, 2 x 26, 4 x 13,.
multipcation is used because its to find out how many things or objects you need if everyone gets a certain amount
4
25, 50, 75, 100, 125, 150, 175, 200, 225, 250, 275, 300, 325 and so on
20
Multiplicative identitya*1 = aReciprocalitya * b = 1then a and b are reciprocals: a = 1/b and b = 1/aAssociativitya * (b * c) = (a * b) * cCommutativitya * b = b * aDistributivitya * (b + c) = a*b + a*c