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Example 27=n3 : Take the cube root of 27. In general find the log, divide it by the power, then take the antilog.
An N3 certificate requires a minimum of four passed technical subjects. N3 subjects are at a level of Matric. N3 certificate must have an addition of two languages to be fully equivalent to a Matric certification.
6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.
47 = 16384 43 = 64 → 47 - 43 = 16384 - 64 = 16320
Input N1, N2, N3 Max = N1 If N2 > Max then Max = N2 If N3 > Max then Max = N3 Display Max