n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
n3
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
The pattern for the nth term is n3. Therefore, the fourth term in the sequence is equal to 43 = 64.
27= 3364=43125=53so next number will be 63 = 216
Cubed integers
n3
There is no pattern
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
The pattern for the nth term is n3. Therefore, the fourth term in the sequence is equal to 43 = 64.
64 Each term number is cubed: 43 = 64
27= 3364=43125=53so next number will be 63 = 216
The sequence 1, 8, 64, 125 consists of perfect cubes: (1^3), (2^3), (4^3), and (5^3). The missing term is (3^3), which is 27. Therefore, the complete sequence would be 1, 8, 27, 64, 125.
1 8 27 64 125 ...13 23 33 43 53 63 73 ...1 8 27 64 125 216 343...
1, 8, 27, 64, 125, 216
1 8 27 64 125 216 343
Cubed integers
Un = 4n - 68