180 - 30
180 - 30
the angle is 180 and its supplement is zero(0).All in degrees
Suppose the angle is x degrees. Then its supplement is 180-x. One-third its supplement is (180-x)/3 = 60-x/3 so x/2 = 60-x/3+25 5x/6 = 85 ie x = 102.
A full circle is 360o, so a quarter, (one fourth) of a circle is 90o.
then WHAT!
45
If one angle is the supplement of another, we know that their sum is 180 degrees.So let one angle be A and the supplement be B. We know the measure of A+B=180.If A is acute that means its measure is less than 90 degrees. The supplement must therefore have measure more than 90 degrees. We could say the supplement of an acute angle must be an obtuse angle. Remember obtuse angle is one that less than 180 degrees and more than 90.
If you add the measure of any angle to its supplementary angle you get 180 degrees. So if the angle is its own supplement, then adding the angle to the angle again (the second one being the supplement) = 180 deg. Thus the angle = 90 degrees.
180 - 30
Supplement angles add up to one hundred eighty degrees, so the supplement of an eighty five degree angle would be a ninety five degree angle.
180 - 30
22.5
Sure - just bisect it twice.
the angle is 180 and its supplement is zero(0).All in degrees
120 Consider: You know that the supplement of an angle is equal to 180 minus the angle. You also know that an angle is twice it's supplement. Now, if you think of angle as being "A", and it's supplement being "S", then we can re-express the above statements like so: S = 180 - A A = 2S Then logically, we can replace the "S" in the second equation with the value we have for it in the first one: A = 2( 180 - A) and then solve that equation: ∴ A = 360 - 2A ∴ A + 2A = 360 ∴ 3A = 360 ∴ A = 360/3 ∴ A = 120
Suppose the angle is x degrees. Then its supplement is 180-x. One-third its supplement is (180-x)/3 = 60-x/3 so x/2 = 60-x/3+25 5x/6 = 85 ie x = 102.