Six side dye. Let x be the random variable, x ={1, 2, 3, 4, 5, 6). The probability for any of the six possible outcomes is P(x) = 1/6. This gives a flat probability distribution.The probability that the outcome in the rolling of one dye is 3 or a smaller number(2 or 1) is; P(x≤3) = P(x=3) + P(x=2) +P(x=1) = 1/6 + 1/6 + 1/6 = 3/6 = 1/2The probability of the complementary event, that the resulting event is a number above 3 is: P(x>3) = 1 - P(x≤3) = 1 - 1/2 = 1/2 = 0.50 = 50%
<p>MCMLXXVI</p> <p>or M + (CM) + (LXX) + VI</p> <p>or M + (M - C) + L + X + X + V + I</p> <p>or 1000 + 900 + 70 + 6</p> <p>or 1976</p>
When two characters are next to each other (like p6) this means multiplication. Therefore it can be written as p x 6. If you substitute p for 3 you have 3 x 6 which equals 18.
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
If B, P, and H are three dimensions ofa rectangular prism them surface area equals 2 x 8 x 3 + 2 x 3 x 6 + 2 x 8 x 6 which equals 180 square meters.
6. all you have to do is use the IS over OF strategy. IS 20% and OF 30 so: P 20 30 100 then cross multiplication: P x 100 = 30 x 20 P x 100/100 = 600/100 P = 6 So there you have it, P = 6
6. all you have to do is use the IS over OF strategy. IS 20% and OF 30 so: P 20 30 100 then cross multiplication: P x 100 = 30 x 20 P x 100/100 = 600/100 P = 6 So there you have it, P = 6
Six side dye. Let x be the random variable, x ={1, 2, 3, 4, 5, 6). The probability for any of the six possible outcomes is P(x) = 1/6. This gives a flat probability distribution.The probability that the outcome in the rolling of one dye is 3 or a smaller number(2 or 1) is; P(x≤3) = P(x=3) + P(x=2) +P(x=1) = 1/6 + 1/6 + 1/6 = 3/6 = 1/2The probability of the complementary event, that the resulting event is a number above 3 is: P(x>3) = 1 - P(x≤3) = 1 - 1/2 = 1/2 = 0.50 = 50%
5.8
24 ============================= Another contributor took issue: You can't tell. There are an infinite number of rectangles with different perimeters that all have the same area. Here are a few with areas of 36: 1 x 36 . . . . . P = 74 2 x 18 . . . . . P = 40 3 x 12 . . . . . P = 30 4 x 9 . . . . . . P = 26 5 x 7.2 . . . . P = 24.4 6 x 6 . . . . . P = 24
<p>MCMLXXVI</p> <p>or M + (CM) + (LXX) + VI</p> <p>or M + (M - C) + L + X + X + V + I</p> <p>or 1000 + 900 + 70 + 6</p> <p>or 1976</p>
To find p(x) / q(x), we first need to substitute the expressions for p(x) and q(x) into the formula. So, p(x) = 20x^5 - 20x^4 + 24x^2 and q(x) = 4x^2. Therefore, p(x) / q(x) = (20x^5 - 20x^4 + 24x^2) / 4x^2. Simplifying this expression, we get 5x^3 - 5x^2 + 6.
When two characters are next to each other (like p6) this means multiplication. Therefore it can be written as p x 6. If you substitute p for 3 you have 3 x 6 which equals 18.
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
ok im gonna show you how this works! :P x/7=6 x/7x7=6x7 x=42
The probability distribution is P(X = 1) = 1/36 P(X = 2) = 3/36 P(X = 3) = 5/36 P(X = 4) = 7/36 P(X = 5) = 9/36 P(X = 6) = 11/36 P = 0 otherwise. Mean(X) = 4.4722 Variance = 1.9715
To calculate the probability of getting at least 6 correct out of 10 questions when guessing on each question, we can use the binomial probability formula. The probability of guessing a question correctly is 1/5, and the probability of guessing incorrectly is 4/5. We need to find the sum of the probabilities of getting 6, 7, 8, 9, or 10 questions correct. This involves calculating the individual probabilities of each scenario using the binomial probability formula and then adding them together.