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∙ 12y agoGiven a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
You a goofy shoty B.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
That will depend entirely on what kind of problem is given but in general the equation of straight line to be plotted on the Cartesian plane is y = mx+b whereas m is the slope of the line and b is the point where it intercepts the y axis.
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
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If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
You a goofy shoty B.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
Consider the numbers A and B where A has m digits after the decimal point and B has n digits.Then find the multiple A'*B' where A' is A without its decimal point, and B' is B without its decimal point.In that answer insert the decimal point so that there are (m+n) digits after the decimal point.
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
Establishing equivalence depends on the definition of parallel lines. If they are defined as lines which cannot ever meet (have no point in common), then the relation is not reflexive and so cannot be an equivalence relation.However, if the lines are in a coordinate plane and parallel lines are defined as those which have the same gradient then:the gradient of a is the gradient of a so the relationship is reflexive ie a ~ a.if the gradient of a is m then b is parallel to a if gradient of b = m and, if the gradient of b is m then b is parallel to a. Thus the relation ship is symmetric ie a ~ b b ~ a.If the gradient of a is m then b is parallel to a if and only if gradient of b = gradient of a, which is m. Also c is parallel to b if and only if gradient of c = gradient of b which is m. Therefore c is parallel to a. Thus the relation is transitive, that is a ~ b and b ~ c => a ~ c.The relation is reflexive, symmetric and transitive and therefore it is an equivalence relationship.
Point slope? y=mx+b M being the slope, and b being the y-intercept.
Start with b. To do this, plot the point (0, b). "Begin with B and Move with M!"