If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a)
If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get:
y = m(x-a) + b
The standard form of the equation is 2x - y + 5 = 0
Points: (2, 2) and (6, 3) Slope: 1/4 Equation: y = 1/4x+3/2 In standard form: x-4y+6 = 0
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
If it passes through the origin
y = 0. You can get this from the slope-intercept equation of the line.
The standard form of the equation is 2x - y + 5 = 0
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Points: (2, 2) and (6, 3) Slope: 1/4 Equation: y = 1/4x+3/2 In standard form: x-4y+6 = 0
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
It is (x + 2)^2 + (y + 3)^2 = 9
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
If it passes through the origin
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If you mean line of 3x+2y = 5 then y = -3/2x+2.5 Perpendicular slope: 2/3 Perpendicular equation: 3y = 2x+18 or as 2x-3y+18 = 0
The equation is: y = 4x-22
y = 0. You can get this from the slope-intercept equation of the line.