Wiki User
∙ 12y agoTotal number of possible outcomes = 6.
Number of them that are more than 2 = 4. (3, 4, 5, and 6)
Probability of rolling more than 2 = 4/6 = 2/3 = 662/3%
Wiki User
∙ 12y agoThe probability is 26/36 = 13/18.
On a single roll it is 2/3.
The probability of rolling more than a six with one roll of a cube whose sides are marked from 1 to 6 is zero.
3/6 because there are 3 numbers over 3 on the dice and it is out of all of it-6
On a single roll of a fair die, the probability is 1/3.
The probability is 26/36 = 13/18.
It is 5/6.
On a single roll it is 2/3.
The probability of rolling more than a six with one roll of a cube whose sides are marked from 1 to 6 is zero.
3/6 because there are 3 numbers over 3 on the dice and it is out of all of it-6
Two thirds (2/3)
On a single roll of a fair die, the probability is 1/3.
The probability is certain or 1. The max you can roll is 12 so it is certain the sum will be less than 13.
A die normally has six sides with the numbers 1 to 6 on them, so any roll will be less than 10 and thus the probability of getting less than 10 with a die is 1. With two normal dice, the sum of the digits on the dice added together ranges from 2 to 12 and the probability of getting less than 10 is the same as 1 minus the probability of getting 10 or more. There are 36 ways the two dice can fall and 10 can be achieved in 3 ways (4&6, 5&5, 6&4), 11 can be achieved in 2 ways (5&6, 6&5) and 12 in 1 way (6&6). Thus the probability of getting 10 or more with 2 dice is (3+2+1)/36 = 6/36 = 1/6 So the probability of getting less than 10 is 1-1/6 = 5/6
Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3
10/13
I am assuming that this die is fair die and the coin is not biased. The probability of getting a number less than 3 is the probability of rolling a 1 or a 2 i.e. 1/6 + 1/6 = 2/6 which simplifies to 1/3. The probability of getting a head when you flip a fair coin is 1/2. Both are independent events, so the probability of getting a number less than 3 and getting a head is 1/3 x 1/2 = 1/6. One can get the same answer from a sample space diagram