It is 0.5
A fair die is a die where the probability of throwing each of the faces is equal. Dice is two or more die's.
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
The probability is 0.5
The probability of getting any outcome is 100%.The probability of a specific outcome depends on the description of that outcome.Some outcomes are more probable. Some are less probable.
The probability of flipping a fair coin four times and getting four heads is 1 in 16, or 0.0625. That is simply the probability of one head (0.5) raised to the power of 4.
The experiment is undefined. On a single roll of eight or more normal dice the probability of getting a sum of 7 is 0.
It is 0.5
A fair die is a die where the probability of throwing each of the faces is equal. Dice is two or more die's.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
The probability is 0.5
The probability of getting any outcome is 100%.The probability of a specific outcome depends on the description of that outcome.Some outcomes are more probable. Some are less probable.
10/13
The experiment is not defined! The probability of the event described, when 9 or more number cubes are rolled, is 0.
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75