Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.
It would have been possible to give a simple answer if we could see what proportion of the way from A to B the question was about. But, thanks to the wonderful (not!) browser used by this site, we cannot and so this is a general answer.If the question was about p/q of the way, then the coordinates of the point are [(14*(q-p) + 4*p)/q, (1*(q-p) + 23*p)/q].
direct proportion indirect proportion additive proportion partitive proportion
If n*p is greater than or equal to 5 AND n*q is greater than or equal to 5, you can use a normal distribution as an estimate for the binomial distribution. Recall, n is the number of trials, p is the probability of success of a trial, and q is 1-p.
a proportion that is open
Two ratios, p/q and r/s (q and s non-zero) are equal if p/q - r/s = 0.
It would have been possible to give a simple answer if we could see what proportion of the way from A to B the question was about. But, thanks to the wonderful (not!) browser used by this site, we cannot and so this is a general answer.If the question was about p/q of the way, then the coordinates of the point are [(14*(q-p) + 4*p)/q, (1*(q-p) + 23*p)/q].
The proportion of the population with a standard of living below the poverty line The Head Count Index (H) is the proportion of the population whose economic welfare (y) is less than the poverty line (z). If q people are deemed to be poor in a population of size n then H=q/n. For computing the Head Count Index, estimates of individual economic welfare and the poverty line are required.
direct proportion indirect proportion additive proportion partitive proportion
95% CI for Proportion is p +/- E; where E = Z*sqrt(p*q/n). P=.6, q=.4, n=144, Z=1.96. Therefore E=1.96*sqrt(0.4*0.6/144) = 0.08. So, 95% CI = .6 +/- 0.08 or .52 to .68.
... a proportion.... a proportion.... a proportion.... a proportion.
the three kinds of proportions are indirect proportion, direct proportion and thepartitive proportion
There cannot be a "proportion of something": proportion is a relationship between two things, and how you solve it depends on whether they (or their transformations) are in direct proportion or inverse proportion.
direct proportion: y=kx inverse proportion: y=k/x
Yes, they are in the proportion of the proportion that they form!
If n*p is greater than or equal to 5 AND n*q is greater than or equal to 5, you can use a normal distribution as an estimate for the binomial distribution. Recall, n is the number of trials, p is the probability of success of a trial, and q is 1-p.
a proportion that is open