Q equals 100 Q/5=20 Multiply by 5 on each side 5(Q/5)=20 Q=100
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
28
Suppose the value of whatever it is, is P in the first year and Q in the next. Then the percentage change is 100*(P - Q)/Q or, equivalently, 100*(P/Q - 1)
P + Q = 180 P = 4Q + 30 So (4Q + 30) + Q = 180 ie 5Q = 150 or Q = 30 Then P = 4Q + 30 = 150
To find the frequency of the "r" allele (q) in the population, divide the number of red organisms by the total number of organisms: 59/100 = 0.59. So, q = 0.59.
If 59 out of 100 organisms are P, then the remaining organisms would be Q. Therefore, Q would be 41 out of 100 organisms.
.77
Q-T- Hush - 1960 The Red-Eyed Raven Caper Strange Reward 1-30 was released on: USA: 1960
There are 100 questions in this quiz.
To calculate q, you first need to determine the frequency of the recessive allele in the population, which can be done using the Hardy-Weinberg equation. In this case, since 11 out of 100 individuals are showing the recessive trait (green color), the q² value is 0.11 (11/100). Therefore, q, the frequency of the recessive allele, would be the square root of 0.11, which is approximately 0.33.
100 zeroes in a googal... the 'q' is a typo for a 'g'
Q equals 100 Q/5=20 Multiply by 5 on each side 5(Q/5)=20 Q=100
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
100 telegram from the queen
If the green allele is recessive and there are 28 organisms with green eyes, then the frequency of the green allele (q) would be √(28/Total organisms) = √(28/Total organisms). Since p+q=1, p = 1 - q. Substituting 28 for q gives 1 - √(28/Total organisms).
(q + 6) (q + 5) = q2 + 11q + 30