If 30 out of 100 organisms are red, then the proportion of red organisms can be represented as ( q = \frac{30}{100} = 0.3 ) or 30%. Therefore, ( q ) is 0.3.
The question seems to be missing context regarding what "q" represents. If "q" refers to a proportion or percentage of red organisms, you could express it as a fraction of the total: for 59 red organisms out of 100, q would be 0.59 or 59%. If all 100 organisms are red, then q would be 1 or 100%. Please clarify if you need a different interpretation.
Q equals 100 Q/5=20 Multiply by 5 on each side 5(Q/5)=20 Q=100
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
28
Suppose the value of whatever it is, is P in the first year and Q in the next. Then the percentage change is 100*(P - Q)/Q or, equivalently, 100*(P/Q - 1)
The question seems to be missing context regarding what "q" represents. If "q" refers to a proportion or percentage of red organisms, you could express it as a fraction of the total: for 59 red organisms out of 100, q would be 0.59 or 59%. If all 100 organisms are red, then q would be 1 or 100%. Please clarify if you need a different interpretation.
To find the frequency of the "r" allele (q) in the population, divide the number of red organisms by the total number of organisms: 59/100 = 0.59. So, q = 0.59.
If 59 out of 100 organisms are P, then the remaining organisms would be Q. Therefore, Q would be 41 out of 100 organisms.
.77
If the purple allele (p) is dominant, then the red phenotype must be associated with the recessive allele, which we can represent as q. Given that 76 out of 100 plants are red, this means that 24 are purple. Assuming Hardy-Weinberg equilibrium, the frequency of the red phenotype (q^2) is 0.76, so q is the square root of 0.76, which is approximately 0.87. Therefore, the frequency of the purple allele (p) is 1 - q, which is roughly 0.13.
Q-T- Hush - 1960 The Red-Eyed Raven Caper Strange Reward 1-30 was released on: USA: 1960
There are 100 questions in this quiz.
To calculate q, you first need to determine the frequency of the recessive allele in the population, which can be done using the Hardy-Weinberg equation. In this case, since 11 out of 100 individuals are showing the recessive trait (green color), the q² value is 0.11 (11/100). Therefore, q, the frequency of the recessive allele, would be the square root of 0.11, which is approximately 0.33.
100 zeroes in a googal... the 'q' is a typo for a 'g'
Q equals 100 Q/5=20 Multiply by 5 on each side 5(Q/5)=20 Q=100
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
100 telegram from the queen