To find side ( a ) in a triangle, we can use the Pythagorean theorem if it is a right triangle, which states ( a^2 + b^2 = c^2 ). Given side ( b = 12 ) and side ( c = 18 ), we can rearrange the equation to find ( a ):
[ a^2 = c^2 - b^2 ] [ a^2 = 18^2 - 12^2 ] [ a^2 = 324 - 144 ] [ a^2 = 180 ] Thus, ( a = \sqrt{180} \approx 13.42 ).
It depends on the shape of the object.
You have not indicated which side the angle is opposite of. Can us law of cosines then by calling sides c and a. b^2 = a^2 + c^2 - 2(a)(c) cos(B) I would arbitrarily have to assign values you have not given me.
In order of length a + b + c = 58; a = 2c, b = c + 10; Substitute: 2c + (c + 10) + c = 58 Gather: 4c + 10 = 58 c = 48/4 = 12 Sides are therefore 24 cm, 22 cm and 12 cm.
A triangle with side a: 10, side b: 8, and side c: 12 meters has an area of 39.69 square meters.
a - b = cAdd 'b' to each side of the equation:a = c + b
What is an angle in the triangle
It depends on the shape of the object.
The answer depends on whether side a is the hypotenuse or side c. If side a is the hypotenuse, then c = 13.416 inches (approx) and if side c is the hypotenuse, then c = 21.633 inches (approx).
A. 12 and 18
The answer is that b = 12 units in length
1.d 2.b 3.c 4.b 5.b 6.d 7.c 8.b 9.a 10.c 11.b 12.b 13.c 14.a 15.b 16.b 17.c 18.a 19.b 20.c 21.c 22.a 13.c .
Tan refers to the ratio of the opposite side of an angle to an adjacent side in a right triangle. For instance, consider a triangle with sides A B C, and angles a b c, where angle a is opposite side A, angle b is opposite side B, and angle c is opposite side C. Angle c is a right angle, and side C is the hypotenuse. Therefore: Tan angle a = side A divided by side B
You have not indicated which side the angle is opposite of. Can us law of cosines then by calling sides c and a. b^2 = a^2 + c^2 - 2(a)(c) cos(B) I would arbitrarily have to assign values you have not given me.
A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
In order of length a + b + c = 58; a = 2c, b = c + 10; Substitute: 2c + (c + 10) + c = 58 Gather: 4c + 10 = 58 c = 48/4 = 12 Sides are therefore 24 cm, 22 cm and 12 cm.
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A triangle with side a: 10, side b: 8, and side c: 12 meters has an area of 39.69 square meters.