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Last year exam question of bca 1 sem?
sin60+cos135 /sin60*cos135
The hypotenuse of a 30-60-90 triangle has a length of 15 what is the length of the side opposite the 60 angle?
The length of the side opposite the 60° angle is: 12.99 units.The long leg is (sin60°)h = 0.866 h = 12.99
What is the hypotenuse of a 30-60-90 triangle if the long leg is 4?
Sin60=4/H where H is the length of the hypotenuse. So H = 4/sin(60) = 4/[sqrt(3)/2] = 8/sqrt(3) = 4.62 units (approx)
What is the area of a parallelogram with sides of 12 cm and 16 cm and an included angle of 60 degrees?
To find the area you would first have to find the height of the parallelogram. Height: Sin60=x/12cm .866=x/12cm 10.4cm=x With the height you can then find the area Area = Base * Height Area=16cm*10.4cm Area=166.3cm^2
In a 30-60-90 right triangle the length of the long leg is 5 what is the length of the hypotenuse is?
use Pythagorean theorem. A squared+ B squared= C squared. the you square root C squared.from superscot85: ...which is fine if you know two of the sides, which you don't. The side opposite the 60o angle is 5, so the hypotenuse is 5/sin60 ie 5.77. (Now you can use Pythagoras to get the short side: sqrt(5.772 - 52) ie sqrt 8.293 which is 2.88.)
Last year exam question of bca 1 sem?
sin60+cos135 /sin60*cos135
What is the sine of 60?
sin60° = √3/2
What is the value of sin60?
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
Cos 60 equals and sin 60 equals?
cos60= 1/2 sin60=1.732/2
The hypotenuse of a 30-60-90 triangle has a length of 15 what is the length of the side opposite the 60 angle?
The length of the side opposite the 60° angle is: 12.99 units.The long leg is (sin60°)h = 0.866 h = 12.99
What is the hypotenuse of a 30-60-90 triangle if the long leg is 4?
Sin60=4/H where H is the length of the hypotenuse. So H = 4/sin(60) = 4/[sqrt(3)/2] = 8/sqrt(3) = 4.62 units (approx)
Two golfers each hit a ball at the same speed only one with a horizontal angle of 60degrees and one at 30degrees which ball goes farther?
The balls go the same distance. The ratio of the distances travelled is Sin30Cos30/Sin60Cos60. Since Sin30=Cos 60, and Cos30=Sin60, the ratio is 1; hence, the distances are the same.
Why is Angle A of a right triangle measures 30 Side b measures 57 yd Find the measures of the parts of the right triangle that are not given Round your answers to the nearest whole number?
since its a right triangle that means that Angle C is 90 degrees. With this knowledge you can find the degree of angle B by taking 180-90-30=60. Now use the law of Sines: Sin of angle A/ length of side a * sin of angle B/ length of side b Ergo: sin30/a * sin60/57 a=19rad3 or 32.9 so 33 sin60/57 * sin90/c c=58rad3 or 65.81 so 66 Now you have: Angle A=30 Angle B=60 Angle C=90 Side a=33 Side b=57 Side c=66
What is the area of a parallelogram with sides of 12 cm and 16 cm and an included angle of 60 degrees?
To find the area you would first have to find the height of the parallelogram. Height: Sin60=x/12cm .866=x/12cm 10.4cm=x With the height you can then find the area Area = Base * Height Area=16cm*10.4cm Area=166.3cm^2
In a 30-60-90 right triangle the length of the hypotenuse is?
You need the length of a side. Try sketching different size triangles with 30/60/90 degree angles - there's an infinite number of them. The length of the hypotenuse is the shortest side / sin30 or the third side / sin60. As sin 30 is 0.5 then the hypotenuse is twice the length of the shortest side (or the third side divided by ½root3 ).
What is the area of an equilateral triangle whose sides measure 8cm?
You can use the 1/2 x a x b x SinC formulaTake 2 sides and an angle in betweenYou know the angles in an equilateral triangle are 60o each. All the sides are 8cm.Plug the values of the sides into a and bPlug the value of the angle into C. You get1/2 x 8 x 8 x Sin60 = 27.7cm2
A 30-60-90 triangle has its longer leg of length 7.8 what is the length of the shorter of the two legs?
The shorter leg is 1/2 of the hypotenuse, while the longer leg is (sin60°) times the hypotenuse or about 0.866 times as long. (7.8/0.866) gives the hypotenuse as 9.0 and 9.0/2 = about 4.5 unitsor use the tangent ratio:7.8/tan 60° = 4.5033321 or about 4.5 in length
