sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
sin60° = √3/2
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Find the value of the fraction.Find the value of the fraction.Find the value of the fraction.Find the value of the fraction.
The value is 300.
what is value of 5 in 17593 what is value of 5 in 17593 what is value of 5 in 17593
sin60+cos135 /sin60*cos135
sin60° = √3/2
cos60= 1/2 sin60=1.732/2
The sine of 60 degrees, denoted as sin(60°), is equal to √3/2. This value arises from the properties of a 30-60-90 triangle, where the ratio of the lengths of the sides opposite the angles is well-defined. Therefore, sin(60°) is approximately 0.866.
You can use the 1/2 x a x b x SinC formulaTake 2 sides and an angle in betweenYou know the angles in an equilateral triangle are 60o each. All the sides are 8cm.Plug the values of the sides into a and bPlug the value of the angle into C. You get1/2 x 8 x 8 x Sin60 = 27.7cm2
The length of the side opposite the 60° angle is: 12.99 units.The long leg is (sin60°)h = 0.866 h = 12.99
Sin60=4/H where H is the length of the hypotenuse. So H = 4/sin(60) = 4/[sqrt(3)/2] = 8/sqrt(3) = 4.62 units (approx)
The balls go the same distance. The ratio of the distances travelled is Sin30Cos30/Sin60Cos60. Since Sin30=Cos 60, and Cos30=Sin60, the ratio is 1; hence, the distances are the same.
since its a right triangle that means that Angle C is 90 degrees. With this knowledge you can find the degree of angle B by taking 180-90-30=60. Now use the law of Sines: Sin of angle A/ length of side a * sin of angle B/ length of side b Ergo: sin30/a * sin60/57 a=19rad3 or 32.9 so 33 sin60/57 * sin90/c c=58rad3 or 65.81 so 66 Now you have: Angle A=30 Angle B=60 Angle C=90 Side a=33 Side b=57 Side c=66
To find the area you would first have to find the height of the parallelogram. Height: Sin60=x/12cm .866=x/12cm 10.4cm=x With the height you can then find the area Area = Base * Height Area=16cm*10.4cm Area=166.3cm^2
You need the length of a side. Try sketching different size triangles with 30/60/90 degree angles - there's an infinite number of them. The length of the hypotenuse is the shortest side / sin30 or the third side / sin60. As sin 30 is 0.5 then the hypotenuse is twice the length of the shortest side (or the third side divided by ½root3 ).
The shorter leg is 1/2 of the hypotenuse, while the longer leg is (sin60°) times the hypotenuse or about 0.866 times as long. (7.8/0.866) gives the hypotenuse as 9.0 and 9.0/2 = about 4.5 unitsor use the tangent ratio:7.8/tan 60° = 4.5033321 or about 4.5 in length