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What is the area of a triangle with angles of 50 60 and 70 degres when the radius of its circumcircle is 10cm?
From the given information and transposing the relevant formulae its area works out as 200*sin(50)*sin(60)*sin(70) = 124.6810383 or about 125 square cm
What is the height of a triangle when the distance between angles 62 degrees and 48 degrees is 1.8 cm?
There is probably a trick that I don't know (can't think of at the moment), but you can use the sine rule and sine ratio: The third angle is 180° - (62° + 48°) = 70° and is opposite the side of length 1.8cm. The side opposite the 48° can be found using the sine rule: a/sin A = b/sin B → a = b × sin A/sin B = 1.8 cm × sin48° / sin 70° The height can now be found using the sine ratio on the 62° angle as the side just found is the hypotenuse of that triangle: sine = opp/hyp → opp = hyp × sine → height = (1.8 cm × sin48° / sin 70°) × sin 62° → height = 1.8 × sin 48° × sin 62° / sin 70° cm ≈ 1.3 cm
What is the perimeter of a regular nonagon that has an area of 395.6367484 square cm?
The regular nonagon will consist of 9 congruent isosceles triangles with base angles of 70 degrees and an apex angle of 40 degrees. Its 2 equal sides: square root of 385.6367484*2/sin(40)*9 = 11.6952176 cm Its base: sin(40)*11.6952176/sin(70) = 8 cm Perimeter: 9*8 = 72 cm
When was Sin Sin Sin created?
Sin Sin Sin was created on 2006-05-22.
How do you simplify cos times cot plus sin?
cos*cot + sin = cos*cos/sin + sin = cos2/sin + sin = (cos2 + sin2)/sin = 1/sin = cosec
