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What is the area of a triangle with angles of 50 60 and 70 degres when the radius of its circumcircle is 10cm?
From the given information and transposing the relevant formulae its area works out as 200*sin(50)*sin(60)*sin(70) = 124.6810383 or about 125 square cm
What is the height of a triangle when the distance between angles 62 degrees and 48 degrees is 1.8 cm?
There is probably a trick that I don't know (can't think of at the moment), but you can use the sine rule and sine ratio: The third angle is 180° - (62° + 48°) = 70° and is opposite the side of length 1.8cm. The side opposite the 48° can be found using the sine rule: a/sin A = b/sin B → a = b × sin A/sin B = 1.8 cm × sin48° / sin 70° The height can now be found using the sine ratio on the 62° angle as the side just found is the hypotenuse of that triangle: sine = opp/hyp → opp = hyp × sine → height = (1.8 cm × sin48° / sin 70°) × sin 62° → height = 1.8 × sin 48° × sin 62° / sin 70° cm ≈ 1.3 cm
What is the perimeter of a regular nonagon that has an area of 395.6367484 square cm?
The regular nonagon will consist of 9 congruent isosceles triangles with base angles of 70 degrees and an apex angle of 40 degrees. Its 2 equal sides: square root of 385.6367484*2/sin(40)*9 = 11.6952176 cm Its base: sin(40)*11.6952176/sin(70) = 8 cm Perimeter: 9*8 = 72 cm
When was Sin Sin Sin created?
Sin Sin Sin was created on 2006-05-22.
How do you simplify cos times cot plus sin?
cos*cot + sin = cos*cos/sin + sin = cos2/sin + sin = (cos2 + sin2)/sin = 1/sin = cosec
What is sin 70?
sin 70 deg. = 0.9397
What is sine of 70 degrees?
sin(70 deg) = 0.9397 approx.
Cot 70 plus 4cos70 equals?
cot 70 + 4 cos 70 = cos 70 / sin 70 + 4 cos 70 = cos 70 (1/sin 70 + 4) = cos 70 (csc 70 + 4) Numerical answer varies, depending on whether 70 is in degrees, radians, or grads.
What is the area of a regular nonagon with a perimeter of 144 inches?
A nonagon is a nine-sided polygon. The area of a regular polygon is:A = (n/4)(s^2)[cos (180° /n)]/[sin (180° /n)]So the area of the nonagon with side 16 (144/9) is:A = (9/4)(16^2)[[cos(180°/9)]/[sin (180°/9)]]= (2.25)(256)[(cos 20°)/(sin 20°)]A ≈ 1,582.55 ft^2 If you don't know the formula of the area of a polygon, you can find its area by multiplying by 9 the area of one of the 9 congruent isosceles triangles that are formed by connecting the center of the polygon with its vertices. But for this you need to find the altitude and the length of the side (which is the radius of the circumscribed circle) of that triangle such as:we know the length base which is 16 ft (144/9), the angle base which is 70 (140/2), and the vertex angle which is 40 (360°/9 or 180° - 140°). By using the Law of Sines we can find the length of r. So,r/sin 70° = 16/sin 40° multiply by sin 70° to both sides;r = (16 sin 70°)/sin 40° sin 70 = altitude/radiusaltitude = (sin 70)(radius) = (Sin 70)[(16 sin 70)/sin 40]altitude = [16(sin 70)^2]/sin 40Thus the area of this nonagon is:A = 9[(1/2)(bh)] where b = 16 and h = [16(sin 70)^2]/sin 40A = (4.5)(16) [[16(sin 70)^2]/sin 40] A ≈ 1,582.55 ft^2
What is the area of a triangle with angles of 50 60 and 70 degres when the radius of its circumcircle is 10cm?
From the given information and transposing the relevant formulae its area works out as 200*sin(50)*sin(60)*sin(70) = 124.6810383 or about 125 square cm
What is the height of a triangle when the distance between angles 62 degrees and 48 degrees is 1.8 cm?
There is probably a trick that I don't know (can't think of at the moment), but you can use the sine rule and sine ratio: The third angle is 180° - (62° + 48°) = 70° and is opposite the side of length 1.8cm. The side opposite the 48° can be found using the sine rule: a/sin A = b/sin B → a = b × sin A/sin B = 1.8 cm × sin48° / sin 70° The height can now be found using the sine ratio on the 62° angle as the side just found is the hypotenuse of that triangle: sine = opp/hyp → opp = hyp × sine → height = (1.8 cm × sin48° / sin 70°) × sin 62° → height = 1.8 × sin 48° × sin 62° / sin 70° cm ≈ 1.3 cm
What is the perimeter of a regular nonagon that has an area of 395.6367484 square cm?
The regular nonagon will consist of 9 congruent isosceles triangles with base angles of 70 degrees and an apex angle of 40 degrees. Its 2 equal sides: square root of 385.6367484*2/sin(40)*9 = 11.6952176 cm Its base: sin(40)*11.6952176/sin(70) = 8 cm Perimeter: 9*8 = 72 cm
Joanna is flying a kite and has let out 70 meters of string and The string makes an angle of 38º with the ground. How far up in the air is the kite?
sin (38) = Altitude / 70Altitude = 70 * sin (38) = 70 * 0.61566 = 43.1 meters(rounded).Probably not quite that high, because no matter what Joanna does, there's no way thekite string is going to perfectly straight, between wind and gravity. So the hypotenuseis actually something less than 70 meters.
What are the release dates for 11-11 En mi cuadra nada cuadra - 2013 Una verdad que lo dejara sin el amor 1-70?
11-11 En mi cuadra nada cuadra - 2013 Una verdad que lo dejara sin el amor 1-70 was released on: USA: 6 September 2013
Write down the acute angle whose sine is equal to Cos 70?
cos70=sin20 so angle is 20, because cosA=sin(90-A)
When was Sin Sin Sin created?
Sin Sin Sin was created on 2006-05-22.
How do you simplify cos times cot plus sin?
cos*cot + sin = cos*cos/sin + sin = cos2/sin + sin = (cos2 + sin2)/sin = 1/sin = cosec
