cot 70 + 4 cos 70 =
cos 70 / sin 70 + 4 cos 70 =
cos 70 (1/sin 70 + 4) =
cos 70 (csc 70 + 4)
Numerical answer varies, depending on whether 70 is in degrees, radians, or grads.
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
Note: When doing trigonometry, it is highly recommeded that you have a scientific calculator at hand. Also, make sure your calculator is in Degree (D or Deg) mode and not Radian (R or Rad). To find the cosine of 70o, press 'cos', then type in 70, then press equals. You should get 0.342 (to the nearest 3 decimal places).
sin(70 deg) = 0.9397 approx.
The standard position of 790 degrees is 70 degrees anticlockwise from the positive x-axis.
This is NOT a Pythagorean triangle. So we must fall back on the Cosine Rule for an agular value. Cosine Rule is a^(2) = b^(2) + c^(2) - 2bcCosA Algebraically rearranging CosA = [a^(2) - b^(2) - c^(2)] / -2bc Substituting CosA = [10^(2) - 7^(2) - 5^)2)] / -(2(7)(5)) CosA = [100 - 49 - 25]/-70 CosA = 26/-70 CosA = -0.371428571... A = Cos^(-1) -0.371428573 A =111.8037 481 ... degrees. - Now area of triangle is 0.5 X Base X height The height is = 7Sin(111.8037481...) Hence are is 0.5(5)(7)Sin(111.8037481...) Area = 16.248... m^(2)
It is 140.
4.48+70 equals to 74.48. Thank you
67 plus 3 equals 70.
it equals 70
70 + 490 = 560
180
190
145
70 + 9.5
390
It equals 70
30