answersLogoWhite

0

cot 70 + 4 cos 70 =

cos 70 / sin 70 + 4 cos 70 =

cos 70 (1/sin 70 + 4) =

cos 70 (csc 70 + 4)

Numerical answer varies, depending on whether 70 is in degrees, radians, or grads.

User Avatar

Wiki User

15y ago

What else can I help you with?

Continue Learning about Trigonometry

What is tan20tan32 plus tan32tan38 plus tan38tan20?

This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1


How do you get cosine of 70 degrees?

Note: When doing trigonometry, it is highly recommeded that you have a scientific calculator at hand. Also, make sure your calculator is in Degree (D or Deg) mode and not Radian (R or Rad). To find the cosine of 70o, press 'cos', then type in 70, then press equals. You should get 0.342 (to the nearest 3 decimal places).


What is sine of 70 degrees?

sin(70 deg) = 0.9397 approx.


What is the standard position of 790?

The standard position of 790 degrees is 70 degrees anticlockwise from the positive x-axis.


A triangular plot of land has sides that measure 5 meters 7 meters and 10 meters What is the area of this plot of land to the nearest tenth of a square meter?

This is NOT a Pythagorean triangle. So we must fall back on the Cosine Rule for an agular value. Cosine Rule is a^(2) = b^(2) + c^(2) - 2bcCosA Algebraically rearranging CosA = [a^(2) - b^(2) - c^(2)] / -2bc Substituting CosA = [10^(2) - 7^(2) - 5^)2)] / -(2(7)(5)) CosA = [100 - 49 - 25]/-70 CosA = 26/-70 CosA = -0.371428571... A = Cos^(-1) -0.371428573 A =111.8037 481 ... degrees. - Now area of triangle is 0.5 X Base X height The height is = 7Sin(111.8037481...) Hence are is 0.5(5)(7)Sin(111.8037481...) Area = 16.248... m^(2)