Because infinity is not a umber, it is usually not treated as a number when computing functions. Instead, you can look for a limit of a function as it approaches infinity. For example, the limit as x approaches infinity of 1/x is 0. Because sine oscillates, it's value constantly moves up and down, and it's value as it approaches infinity is not defined because it does not converge on any one number, as some other functions (like 1/x) do.
There is no fixed limit. A periodic function, such as the sine function, can have an infinite number of x-inercepts.
In a basic sine curve, zeros cannot be found at points where the sine function is not defined, such as at infinite values of the input variable. However, in the context of a standard sine function defined on the real numbers, zeros occur at integer multiples of π (πn, where n is an integer). Therefore, the only points where zeros cannot be found are those that do not correspond to these integer multiples.
sine 810 = sine 90 = 1
Sine(A+ B) = Sine(A)*Cosine(B) + Cosine(A)*Sine(B).
Sine 3.3 degrees is about 0.057564. Sine 3.3 radians is about -0.157746. Sine 3.3 grads is about 0.051813.
It is infinite, in both directions. But it can be restricted to a smaller interval.
There is no fixed limit. A periodic function, such as the sine function, can have an infinite number of x-inercepts.
In a basic sine curve, zeros cannot be found at points where the sine function is not defined, such as at infinite values of the input variable. However, in the context of a standard sine function defined on the real numbers, zeros occur at integer multiples of π (πn, where n is an integer). Therefore, the only points where zeros cannot be found are those that do not correspond to these integer multiples.
Every periodic signal can be decomposed to a sum (finite or infinite) of sines and cosines according to fourier analysis.
spectrum of sinewave contains how many components The spectrum of a pure sine wave by definition has only one component. Any other periodic wave will additional components at multiples of the fundemental frequency. The spectrum may or may not extend to infinity. A square wave for example has infinite harmonics, the harmonics of a 'modified sine wave' inverter has lower harmonics than a square wave but still has infinite harmonics. As you get closer to a pure sinusiod the energy content of the higher harmonics will be essentially non existent. It all depends how close the wave approximates a pure sinusoid.
sine 810 = sine 90 = 1
There are an infinite number. The simplest is a sinusoid. The sine function has period 2π, so you compress it by a factor of π: f(x) = sin (πx).
Sine(A+ B) = Sine(A)*Cosine(B) + Cosine(A)*Sine(B).
Sine 3.3 degrees is about 0.057564. Sine 3.3 radians is about -0.157746. Sine 3.3 grads is about 0.051813.
No and yes. Digital signals are usually square or pulse waves. By Fourier analysis, however, every periodic wave, even a square wave, is the summation of some series (often infinite) of sine waves.
Sine does not converge but oscillates. As a result sine does not tend to a limit as its argument tends to infinity. So sine(infinity) is not defined.
Consider that a sawtooth waveform is the summation of the infinite series of sine waves with amplitude equal to 1 over the multiplier of the frequency. Now you can take the derivative, or at least approximate it. You will find that the derivative of a sawtooth is a pulse, in the ideal case, a pulse with infinite amplitude and zero width.