The sum of the digits of a multiple of 3 sum to a number that is itself divisible by 3.
Example : 153 : 1 + 5 + 3 = 9 which is divisible by 3 so 153 is a multiple of 3.
But : 206 : 2 + 0 + 6 = 8 shows that 206 is NOT a multiple of 3.
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No.15 = 3 x 5So for 200 to be a multiple of 15, it must be a multiple of both 3 and 5:2 + 0 + 0 = 2 which is not a multiple of 3 so 200 is not a multiple of 3.200 ends in 0, so it is a multiple of 5.Thus 200 is a multiple of 5, but not a multiple of 3; so it is not a multiple of 15.
Yes. Digit total is 9 which is a multiple of 3 so it is too.
No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.
To determine whether 3 is a multiple of 78, divide 78 by 3. You should get 78 / 3 = 26. So 3 is a multiple of 78. Another way to work out this problem is to add up the digits of 78. 7 + 8 = 15, which is divisible by 3. So 3 is a multiple of 78.
The third multiple of 3 is 9 and the fourth multiple of 4 is 16. So 9 multiplied by 16 is 144.