In order for a number to be divisible by 6 and 9, it has to satisfy two characteristics. 1) it has to be even. 2) the sum of the individual digits must be a multiple of 9 (9, 18, 27, etc). For example, let's see if 126 works. 126 = even 1 + 2 + 6 = 9 Therefore, it is divisible by 6 and 9.
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Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
It is 3 6 9
144 is divisible by: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72 and 144.
NO!!! To test divisibility by '9' add the digits. If the ddigits sum to '9' , then the number is divisible by '9' . Hence 3705 ; 3 + 7 + 0 + 5 = 15 = 1 + 5 = 6 So it does not add to '9' , so it is not divisible by '9'.