The smallest 4 digit number divisible by 50 is 1000, so to have a remainder of 17, it is 1000 + 17 = 1017.
n + 20 - 17 + 13 - n = 20 - 17 + 13 = 3 + 13 = 16
Since 17 is a factor of 119, the remiander will be the same modulo 17. Thus, the remainder, on division by 17 would be 19 except that 19 contains one more 17 - leaving a final remainder of 2.
If x ≡ 39 mod 357 then: x = 357k + 39 for some integer k. Now 357 = 21×17, and 39 = 2×17+5 → x = 21×17×k + 2×17 + 5 → x = 17(21k + 2) + 5 → x = 17m + 5 where m = 21k + 2 (is an integer) → x ≡ 5 mod 17 → the remainder when the number is divided by 17 is 5.
A remainder is the fraction left over as a result of dividing an uneven number. 52 ÷ 3 = 17 with a remainder of 1/3.
"F2013" is not exactly a number. Nor is "F100".
The greatest remainder when dividing by any number is one less than the number itself. The greatest remainder when dividing by 18 is therefore 17. EXAMPLE : 35 ÷ 18 = 1 and remainder 17.
The smallest 4 digit number divisible by 50 is 1000, so to have a remainder of 17, it is 1000 + 17 = 1017.
n + 20 - 17 + 13 - n = 20 - 17 + 13 = 3 + 13 = 16
When dividing any integer by 17, the remainder can range from 0 to 16, as the remainder must be less than the divisor. Therefore, the greatest possible remainder when the divisor is 17 is 16. This means that when any integer is divided by 17, the remainder will be less than 17 but could be as high as 16.
Since 17 is a factor of 119, the remiander will be the same modulo 17. Thus, the remainder, on division by 17 would be 19 except that 19 contains one more 17 - leaving a final remainder of 2.
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If x ≡ 39 mod 357 then: x = 357k + 39 for some integer k. Now 357 = 21×17, and 39 = 2×17+5 → x = 21×17×k + 2×17 + 5 → x = 17(21k + 2) + 5 → x = 17m + 5 where m = 21k + 2 (is an integer) → x ≡ 5 mod 17 → the remainder when the number is divided by 17 is 5.
A remainder is the fraction left over as a result of dividing an uneven number. 52 ÷ 3 = 17 with a remainder of 1/3.
17
306.4706
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 17 is an odd number.