Let the number be x and so the expression is: 3+x^2
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
n+3 the sum of a number and three means a number plus three.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
Let the number be x and so the expression is: 3+x^2
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
A number is divisible by 3 if the sum of its digits is divisible by 3.
When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.
n+3 the sum of a number and three means a number plus three.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
Sum = Sum + first number Sum = Sum + second number Sum = Sum + third number Average = 1/3 x Sum
3
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.