Surface area in square units = pi*radius2
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Pi*6 * * * * * Independent of the radius? Makes no difference if the disc is twice as wide? I think not! It is actually 2*pi*r2 where r is the radius of the disc.
Area of disc: pi*6^2 = 36*pi square cm
The area of a disc of radius R units is pi*r^2 square units.
It is the surface area of the two ends plus the surface area of the curved surface. Surface area of each end is pir2 Surface area of the curved surface is 2pirh Total surface area = 2pir2 + 2pirh
If R and r are the outer and inner radii of the annulus (ring) then the area is pi*(R2 - r2), which is simply the area of the big disc minus that of the little disc.