The area of a disc of radius R units is pi*r^2 square units.
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Area of disc: pi*6^2 = 36*pi square cm
If R and r are the outer and inner radii of the annulus (ring) then the area is pi*(R2 - r2), which is simply the area of the big disc minus that of the little disc.
Surface area in square units = pi*radius2
Pi*6 * * * * * Independent of the radius? Makes no difference if the disc is twice as wide? I think not! It is actually 2*pi*r2 where r is the radius of the disc.
No because the formula for finding the area of an oval, which is an ellipse, is quite different