No, equations with the same slope do not intersect unless they are the same line.
In plain geometry, if 2 lines never intersect, they are Parallel
x = 2 and y =1 so the lines intersect at (2, 1)
They have a starting point, end point, definite length, they connect 2 points, they have a definite slope, they do not always have a y- intersect or x- intersect.
Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3
No, equations with the same slope do not intersect unless they are the same line.
Let x be in A intersect B. Then x is in A and x is in B. Then x is in A.
In plain geometry, if 2 lines never intersect, they are Parallel
The origin is where x axis and y axis intersect.
x = 2 and y =1 so the lines intersect at (2, 1)
They have a starting point, end point, definite length, they connect 2 points, they have a definite slope, they do not always have a y- intersect or x- intersect.
Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3
y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
x = -1 and y = 2 The lines intersect at (-1, 2)
-18 X + Y = 8 ........ 1 -3 X - Y = -2 ........ 2 Summing eq 1 and 2 - 21 X = 6 or X = - 6/21 or -2/7 Multiply eq 2 by 6 and subtract 2 from 1 7 Y = 20 or Y = 20/7 Accordingly, the two equations intersect at point: X = -2/7 and Y = 20/7
Inequalities are defining part of the plane So either they intersect in infinitely many point (either in a part of the plane or on a line) or they don't intersect 1 - zero solution x+y > 1 and x+y <0 2 - infinitely many solution x+y >2 and x + y > 3 (a part of the plane) x+y >=2 and x+y <= 2 (a line)
The symbol commonly used to denote factorial is the exclamation point ( ! ). E.g. 1! = 1 2! = 2 3! = 6 4! = 24 5! = 120 x! = x*(x-1)*(x-2)*(x-3)*(x-4)* ... *3*2*1 , where x is an integer.