x = 2 and y =1 so the lines intersect at (2, 1)
x = -1 and y = 2 The lines intersect at (-1, 2)
x = 3 and y = 2 so the lines intersect at the point (3, 2)
They intersect at the point of: (-3/2, 11/4)
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations
x = 2 and y =1 so the lines intersect at (2, 1)
x = -1 and y = 2 The lines intersect at (-1, 2)
x = 3 and y = 2 (3,2)
x = 3 and y = 2 so the lines intersect at the point (3, 2)
x = 2 and y = 1 The lines intersect at the point (2, 1)
They intersect at the point of: (-3/2, 11/4)
They intersect when 2x + 4 = -x + 1 or 3x = -3 => x = -1 and when x = -1, y = -x + 1 = -(-1) + 1 = 2 So the point of intersection is (-1, 2)
x = 2 and y =-3 so the lines intersect at (2, -3)
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations
y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
No solution. The two lines are parallel and hence never intersect hence no solution.