A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
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s + 3 = 6s -s -s ------------- 3 = 5s /5 /5 s=3/5 or s=.6
Locate the turning point(s) for the following functions. (a) y=x3-x2 -3x + 5 3
3
102 = 100.I don't think it matters what 's' is.
s = -70