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3n(n+1] + 5 is the nth term
22 - 3n
5
The Series has the formula 3n + 1/2(n - 1)(n - 2) = 3n + 1/2(n2 - 3n + 2) which simplifies to, 1/2(n2 +3n + 2)
The 'n'th term is [ 4 - 3n ].