To find the term from the end in the expansion of ( x - 12x^{3n} ), we can first rewrite it as ( x + (-12)x^{3n} ). The expansion of this expression will consist of two terms: ( x ) and ( -12x^{3n} ). The last term, which is the term from the end, is (-12x^{3n}). Therefore, the required term from the end is (-12x^{3n}).
3n(n+1] + 5 is the nth term
22 - 3n
5
The Series has the formula 3n + 1/2(n - 1)(n - 2) = 3n + 1/2(n2 - 3n + 2) which simplifies to, 1/2(n2 +3n + 2)
123456789 * * * * * The nth term is 3n
What is the 2nd term of 3n-2?
you have answered your own question 19 - 3n
Just plug in 30 for n in 3n-1. The answer is 89.
3n(n+1] + 5 is the nth term
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
3,6,9,12
3n +5
3n+7
22 - 3n
8