What is the 2nd term of 3n-2?
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Sn = 3n2 + 2n - 8
t(n) = 3n2 + n = n(3n + 1)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
(3n+2)(n+1)
The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).