What is the 2nd term of 3n-2?
Sn = 3n2 + 2n - 8
t(n) = 3n2 + n = n(3n + 1)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
(3n+2)(n+1)
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence does not appear to follow a simple arithmetic or geometric progression. Therefore, it is likely following a pattern involving squares or cubes of numbers. By examining the differences between consecutive terms, we can deduce the pattern and determine the nth term. In this sequence, the differences between consecutive terms are 9, 15, 21, which are not constant. This suggests a more complex pattern, possibly involving squares or cubes of numbers.
Sn = 3n2 + 2n - 8
t(n) = 3n2 + n = n(3n + 1)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
n1 = 3n2 = 3(3) + 2 = 9 + 2 = 11n3 = 3(11) +2 = 33 + 2 = 35n4 = 3(35) + 2 = 105 + 2 = 107The fourth term in the sequence (n4) is 107.
Formula: (Hg2)3N2
The GCF is 3n.
2NaN ---> 2Na + 3N2
The numbers are generated by Pn = (3n2 - n)/2 for n = 1, 2, 3, ... A list of pentagonal numbers (first 46) is given on the link below.
-((3n - 1)(n + 3))
Maybe: [Cd(NH3)5]3N2