What is the 2nd term of 3n-2?
3n2 + 1Hope this helps :)
Sn = 3n2 + 2n - 8
t(n) = 3n2 + n + 1
t(n) = 3n2 + n = n(3n + 1)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
3n2 + 1Hope this helps :)
Sn = 3n2 + 2n - 8
t(n) = 3n2 + n + 1
t(n) = 3n2 + n = n(3n + 1)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
3
n1 = 3n2 = 3(3) + 2 = 9 + 2 = 11n3 = 3(11) +2 = 33 + 2 = 35n4 = 3(35) + 2 = 105 + 2 = 107The fourth term in the sequence (n4) is 107.
Formula: (Hg2)3N2
2NaN ---> 2Na + 3N2
The GCF is 3n.
The numbers are generated by Pn = (3n2 - n)/2 for n = 1, 2, 3, ... A list of pentagonal numbers (first 46) is given on the link below.