101
128
If the sequence is 205, 306, 427 then a possible 4th number is 568. The initial difference between 205 and 306 is 101, which increases by 20 at each step. 306 → 427 = 121 : 427 → 568 = 141
164,850 Calculated as follows: The lowest number is 101 and the highest number is 998. If you use the theory behind factorials, and pair the numbers, the lowest with the highest (101+998=1,099) then the next lowest and next highest (104+995=1,099), etc. they all add to 1,099. The sequence goes by threes: 101, 104, 107, etc There are 300 total numbers in the sequence (the first is 101, and 299 more (299x3=897)...897+101=998). The actual formula is {(998-101)/3} + 1 = 300 (the 1 is for the first number) So that makes 150 pairs of numbers that = 1,099. 150 x 1,099 = 164,850
No, 101 is not a composite number. It is a prime number because it is only divisible by 1 and itself.
101
7(n2-1) - 4
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
61 81 101 121 141...you get were im coming from!
128
170. 82 + 19 = 101 101 + 21 = 122 122 + 23 = 145 145 + 25 = 170. Difference increases by 2 each time.
The Fledgelins Handbook 101 is available now since October 26th 2010.
The answer depends on what the question is! Is it the rule that is required, or the next term? There are many rules that can be used to generate this sequence. One possibility is Un = (347n5 - 5290n4 + 30685n3 - 82910n2 + 103368n - 45720)/120 for n = 1, 2, 3, ...
Each number describes the one before (the first is arbitrary). 101, two 1s, one 0 2110, one 2, two 1s, one 0.
The answer depends on what the question is! Is it the rule that is required, or the next term? There are many rules that can be used to generate this sequence. One possibility is Un = (347n5 - 5290n4 + 30685n3 - 82910n2 + 103368n - 45720)/120 for n = 1, 2, 3, ...
Yes, 101 is an odd number.101 is an odd number.
If the sequence is 205, 306, 427 then a possible 4th number is 568. The initial difference between 205 and 306 is 101, which increases by 20 at each step. 306 → 427 = 121 : 427 → 568 = 141