It is 162.
How about: 101+23 = 124
To find the sum of the first 100 integers, you first add 1 plus 100 (the first and last numbers of the set) and get 101. Do the same with the next two integers, 2 and 99 and you'll get 101. Since you are adding two integers at a time and there are 100 integers between 1 and 100, you'll get 101, fifty times. Therefore, a shortcut would be to simply multiply 101 times 50 and get 5,050.
The sum of all prime numbers between 1 and 11 is 28.
901
101
101
1 1 1
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
The sum of all the numbers from 101 through 200 is 15,050.
101
If you add the first and the last number, you have a sum of 101. The second number from the left and the second number from the right will also add up to 101. If you continue in this way, you get 50 pairs of numbers, each of which has a sum of 101, so the final result is 50 x 101.
The sum is 7268. * * * * * No. It is 7399. 7500 if 101 is included.
The answer is zero !
2312
1110
The sum of the integers between 101 and 300 inclusive is equal to ((101+300) x 200) / 2 = 40100.