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Let the sides be x, y, z. Let the angles opposite those sides be X, Y, Z You can use the Cosine Law which states cos X = (y^2 + z^2 - x^2)/2yz Then calculate cos^-1(or arccos X) and this will give you the angle in degrees. then do the same for Y cos Y = (x^2 + z^2 - y^2)/2xz Do the same to get Y. Then add X and Y and subtract for 180° and you have your three angles.
There is no answer to y - 2, because y - 2 isn't a question.
y2=26 y2/2 l 26/2 y = 13 when using " 4 line method", the purpose is to isolate the variable. the coefficent states that you're multiplying y by 2, so to isolate the variable, you have to get rid of the 2, which you do by dividing y2 by 2. likewise, if the equation stated y+2, to isolate the variable, you subtract 2. it works the other way aroind, too. if the equation stated y/2, to isolate the variable, you multiply it by 2. the same thing with y-2. you add 2. now, the division property of equality states that when you divide on the left, you divide on the right, too. so when you divide y2 by 2 in order to isolate the variable, you have to divide 26 by 2 as well, giving you your answer of y+13. class is dismissed. ;3
If you mean y/2 + y (without parentheses), y/2 is the same as (1/2)y, and y is the same as 1y. You can use the distributive property to combine this; in this case, the result is (3/2)y.
If you mean: (y-2)(y+2) then it is y^2 -4 which is the difference of two squares