If you mean y/2 + y (without parentheses), y/2 is the same as (1/2)y, and y is the same as 1y. You can use the distributive property to combine this; in this case, the result is (3/2)y.
If you mean: (y-2)(y+2) then it is y^2 -4 which is the difference of two squares
y = 15 so that 13= 15 - 2 y-2 = 13 y-2 +2 = 13 +2 y = 15
2
X - Y = 2 When X = 3 you have 3 - Y = 2 Moving Y to RHS: 3 = Y + 2 Moving 2 to LHS: 1 = Y
(y^2 - 4) / (y + 2) = [(y -2)(y+2)]/(y+2) = y-2
2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)
y-2 +2 y=2 slope is undefined y intercept is 2
When Y = 8, Y - 2 = 6.
is that (y*2)? if yes the answer will be: 2-6y^2
If you mean y/2 + y (without parentheses), y/2 is the same as (1/2)y, and y is the same as 1y. You can use the distributive property to combine this; in this case, the result is (3/2)y.
Y/2
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
The expression y^4 - z^4 can be factored using the difference of squares formula. It can be written as (y^2 + z^2)(y^2 - z^2), which can be further simplified to (y^2 + z^2)(y + z)(y - z).
y3 + 2y2 - 81y -162 = y2(y+2) - 81(y+2) =(y+2)(y2-81) = (y+2)(y-9)(y+9)
y = 3x - 2 3x = y + 2 x = y + 2 --------- 3
If you mean: (y-2)(y+2) then it is y^2 -4 which is the difference of two squares