an = 4n - 14
So
a35 = 35*4 - 14 = 140 - 14 = 126
a(n) = 7n so a(35) = 245
To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values: [ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ] Thus, the 35th term is 126.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
It is the difference between a term (other than the second) and its predecessor.
875
a(n) = 7n so a(35) = 245
To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values: [ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ] Thus, the 35th term is 126.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
It is a + 8d where a is the first term and d is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
14112027
It is the difference between a term (other than the second) and its predecessor.
-13
From any term after the first, subtract the preceding term.
875
Whether the sequence is increasing or decreasing makes no difference. The only difference is that the common difference d will be a negative number.
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.