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To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values:
[ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ]
Thus, the 35th term is 126.
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Find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(n) = 7n so a(35) = 245
What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
How do you find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(1) = 7, a(2) = a(1) + 7, a(3) = a(2) + 7 which = a(1) + 7 + 7 which = 7 + 7 + 7. There are as many multiples of 7 as there are terms, so a(35) = 7 x 35 = 245.
What is the 17th term of the sequence in which a1 equals 7 and the common difference is 3?
U17 = 7 + 3*16 = 7 + 48 = 55
What does common difference mean in math?
In mathematics, the common difference refers to the constant amount that is added or subtracted to each term in an arithmetic sequence to get the next term. It is calculated by subtracting any term from the subsequent term in the sequence. For example, in the sequence 2, 5, 8, 11, the common difference is 3, since each term increases by 3.
Find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(n) = 7n so a(35) = 245
What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
How do you find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(1) = 7, a(2) = a(1) + 7, a(3) = a(2) + 7 which = a(1) + 7 + 7 which = 7 + 7 + 7. There are as many multiples of 7 as there are terms, so a(35) = 7 x 35 = 245.
If a equals 4 and d equals -2 what is the first four terms of the arithmetic sequence?
6
What is the 17th term of the sequence in which a1 equals 7 and the common difference is 3?
U17 = 7 + 3*16 = 7 + 48 = 55
What is the nth term for 1 5 9 13 17?
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
A certain arithmetic sequence has the recursive formula an equals an-1 plus d If the common difference between the terms of the sequence is -11 what term follows the term that has the value 11?
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
What is the nth term in the arithmetic sequence?
It is a + 8d where a is the first term and d is the common difference.
What is the tenth term if the first term is -10 and the common difference is -2?
-8
The nth term -4,-1,4,11,20,31?
14112027
What is the 14 term in arithmetic sequence in which the first term is 100 and the common difference is -4?
100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48
What is the 14th term in an arithmetic sequence in which the first term is 100 and the common difference is -4?
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
