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To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values:
[ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ]
Thus, the 35th term is 126.
What else can I help you with?
Find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(n) = 7n so a(35) = 245
What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
How do you find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(1) = 7, a(2) = a(1) + 7, a(3) = a(2) + 7 which = a(1) + 7 + 7 which = 7 + 7 + 7. There are as many multiples of 7 as there are terms, so a(35) = 7 x 35 = 245.
What is the 17th term of the sequence in which a1 equals 7 and the common difference is 3?
U17 = 7 + 3*16 = 7 + 48 = 55
What is the 14 term in arithmetic sequence in which the first term is 100 and the common difference is -4?
100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48
Find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(n) = 7n so a(35) = 245
What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
How do you find the 35th term of the sequence in which a1 equals 7 and the common difference is 7?
a(1) = 7, a(2) = a(1) + 7, a(3) = a(2) + 7 which = a(1) + 7 + 7 which = 7 + 7 + 7. There are as many multiples of 7 as there are terms, so a(35) = 7 x 35 = 245.
If a equals 4 and d equals -2 what is the first four terms of the arithmetic sequence?
6
What is the 17th term of the sequence in which a1 equals 7 and the common difference is 3?
U17 = 7 + 3*16 = 7 + 48 = 55
What is the nth term for 1 5 9 13 17?
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
A certain arithmetic sequence has the recursive formula an equals an-1 plus d If the common difference between the terms of the sequence is -11 what term follows the term that has the value 11?
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
What is the tenth term if the first term is -10 and the common difference is -2?
-8
What is the nth term in the arithmetic sequence?
It is a + 8d where a is the first term and d is the common difference.
The nth term -4,-1,4,11,20,31?
14112027
What is the 14 term in arithmetic sequence in which the first term is 100 and the common difference is -4?
100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48
What is the 14th term in an arithmetic sequence in which the first term is 100 and the common difference is -4?
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
