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To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values:

[ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ]

Thus, the 35th term is 126.

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3mo ago

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