To find the 50th term of the sequence formed by the digits 0, 3, 6, and 9, we first observe that the sequence repeats every four terms: 0, 3, 6, 9. To determine the 50th term, we calculate the position in the cycle by finding the remainder of 50 divided by 4, which is 2 (since 50 mod 4 = 2). Therefore, the 50th term corresponds to the second term in the repeating sequence, which is 3.
n-9+3
47
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
The sequence 0, 3, 6, 9, 12 is an arithmetic sequence where the first term is 0 and the common difference is 3. The formula for the nth term can be expressed as ( a_n = 3(n - 1) ) or simply ( a_n = 3n - 3 ). This formula generates the nth term by multiplying the term's position (n) by 3 and adjusting for the starting point of the sequence.
To find the 50th term of the sequence formed by the digits 0, 3, 6, and 9, we first observe that the sequence repeats every four terms: 0, 3, 6, 9. To determine the 50th term, we calculate the position in the cycle by finding the remainder of 50 divided by 4, which is 2 (since 50 mod 4 = 2). Therefore, the 50th term corresponds to the second term in the repeating sequence, which is 3.
n-9+3
47
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
The sequence 0, 3, 6, 9, 12 is an arithmetic sequence where the first term is 0 and the common difference is 3. The formula for the nth term can be expressed as ( a_n = 3(n - 1) ) or simply ( a_n = 3n - 3 ). This formula generates the nth term by multiplying the term's position (n) by 3 and adjusting for the starting point of the sequence.
The pattern for the sequence 0 0 1 3 6 is that each term is obtained by adding the previous term multiplied by its position in the sequence (starting from 1). In other words, the nth term is given by n*(n-1)/2.
Vinyl Rewind - 2011 The Freewheelin' Bob Dylan 50th Anniversary 3-6 was released on: USA: 21 May 2013
No - by dividing the numerator and denominator by 2, 6/50 can be reduced to 3/25 or three twenty-fifths.
9. -6+6=0 0+3=3 therefore -6+9=3
0 9-3=6 6-3=3 3-3=0
The range is 6. (6 - 0 = 6)
104