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n-9+3
47
recursive rule: term(n+1) = term(n) + (n) also, n starts at 0 and term(1)=3 term(1) = 3 ; (n=0) term(2) = term(1) + (1) = 4 term(3) = term(2) + (2) = 6 term(4) = term(3) + (3) = 9 term(5) = term(4) + (4) = 13 . . .
The pattern for the sequence 0 0 1 3 6 is that each term is obtained by adding the previous term multiplied by its position in the sequence (starting from 1). In other words, the nth term is given by n*(n-1)/2.
No - by dividing the numerator and denominator by 2, 6/50 can be reduced to 3/25 or three twenty-fifths.