47
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
If the 1st to 5th terms of the sequence are all 5, it suggests that the sequence is constant. Therefore, the 17th term of the sequence would also be 5. Thus, the 17th term is 5.
The 'n'th term is [ 4 - 3n ].
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
55,73and 110
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
5
4,8,12,16,20
If the 1st to 5th terms of the sequence are all 5, it suggests that the sequence is constant. Therefore, the 17th term of the sequence would also be 5. Thus, the 17th term is 5.
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
It works out as -5 for each consecutive term
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
55,73and 110
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
82