47
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
The 'n'th term is [ 4 - 3n ].
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
55,73and 110
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
5
4,8,12,16,20
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
It works out as -5 for each consecutive term
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
55,73and 110
82
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.