The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
The 'n'th term is [ 4 - 3n ].
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
55,73and 110
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
4,8,12,16,20
It works out as -5 for each consecutive term
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
82
55,73and 110
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
6n-5 is the nth term of this sequence