The given sequence is an arithmetic sequence where each term increases by 7. The first term (a) is 3, and the common difference (d) is 7. The formula for the nth term of an arithmetic sequence is given by ( a_n = a + (n - 1) \cdot d ). For the 50th term, ( a_{50} = 3 + (50 - 1) \cdot 7 = 3 + 343 = 346 ).
31
There are very many possible solutions. The simplest polynomial solution is t(n) = (n^4 - 14n^3 + 71n^2 + 14n + 24)/24.
17
14.5
17:50
7n - 4
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term is 7n-4 and so the next number in the sequence is 31
31
24
The sequence progresses by adding 7 to the previous term.The nth term is thus equal to 10 + 7n. The 11th term therefore is equal to 10 + (7 * 11) = 10 + 77 = 87.
17/12 17 over 12
4k + 24 = 6k - 10 subtract 4k from each side 4k - 4k + 24 = 6k - 4k - 10 24 = 2k - 10 add 10 to each side 10 + 24 = 2k - 10 + 10 34 = 2k divide each side integers by 2 17 = k ------------check 4(17) + 24 = 6(17) - 10 68 + 24 = 102 - 10 92 = 92 checks
Subtract 7 from each number, so the 9th number would be 59.
Firstly 10% = 17 and 20% = 34 so answer is between 10% and 20% i.e. 24 is betwen 17 and 34 24 / 170 = 0.1411764 = 14.11764 %
There are very many possible solutions. The simplest polynomial solution is t(n) = (n^4 - 14n^3 + 71n^2 + 14n + 24)/24.
44