You put the four digit number at the top of the three digit number and you do the same thing as you would do with a two digit number with a 3 digit number.
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60. There are 5 different choices for the first digit, four for the second digit, and three choices for the third digit. According to the fundamental counting principle, you multiply them together to get the total number of possible ways, and 5 x 4 x 3 = 60 Another way to think about it is 5!/3!
> 9999876 Actually, 9999876 has four different digits (6, 7, 8, 9). The largest 7-digit number with three different digits is 9999987.
If the number is odd, the last digit is odd. That means the ten's digit must be twice the one's digit. There are only four two-digit numbers where the ten's digit is twice the one's digit: 21, 42, 63, 84. Check which of these satisfy all the clues.
1634, 8208 and 9474 See related link.
1 3 4 9
2178
300
3333
2400
I think you mean, the largest four digit number that has exactly three divisors. 2X3X1663=9,978
Any three digit number which is in the four times table. E.g 100, 104, 108 ... 992, 996.
Four. (100 x 10 = 1,000)
999 - 1000
It can have one . . . 1.0 x 1.0 = 1 It can have two . . . 1.0 x 0.1 = 0.1 It can have three . . . 10 x 10 = 100 It can have four . . . 99 x 99 = 9801 and .01 x .01 = .0001
You're looking for a 4-digit number that is divisible by 11 and 17. Multiply them together. Put a zero on the end. 1870
If there is a decimal placed somewhere within the number, such as .3568 could be rounded to .357
182