They are the 62 terms of the sequence:
t(n) = 61!/[n1*(61-n)!] for n = 0, 1, 2, ... , 61.
n! denotes a*2*3* ... *n
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1,4,6,4,1
The sum is 24 = 16
If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.
1 5 10 10 5 1
The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16. Formula 2n-1 where n=5 Therefore 2n-1=25-1= 24 = 16.