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What is the number of ways of forming 6 digit number whose sum of digits is even?
I look at it this way:-- There are 90,000 numbers with five digits. (100,000 minus 10,000 with less than 5 digits)-- If the sum of the first 5 digits is odd, it can be made even by using 1, 3, 5, 7, or 9for the 6th digit ... 5 choices.-- If the sum of the first 5 digits is even, it remains even by using 2, 4, 6, 8, or 0for the 6th digit ... 5 choices.-- So, for any one of the 90,000 five-digit numbers, there are 5 choices for the 6th digitthat result in an even sum of all six.-- So, there must be 450,000 suitable 6-digit numbers.
How do you expand 9 digit numbers?
100000000*first digit+10000000*second digit+1000000*third digit+100000*fourth digit+10000*fifth digit+1000*sixth digit+100*seventh digit+10*eightth digit+1*nineth digit
My tens digit is 4 less than my thousand digit. My ones digit is twice my tens digit.My ten thousand digit is one less than my ones digit. my hundreds digit is the sum of my tens and thousand digit.?
I am a four digit number. My tens digit is 2 more than my ones digit. My hundreds and thousands digit are both 1 less than my ones digit. What number can i be?
My tens digit is 2 times your hundreds digit My hundreds digit is 4 My ones digit is a factor of your tens and hundreds digit Who am I?
one
What are two three digit numbers the tens digit is half the hundreds digit and the ones digit is half the tens digit?
421 and 842
