I look at it this way:-- There are 90,000 numbers with five digits. (100,000 minus 10,000 with less than 5 digits)-- If the sum of the first 5 digits is odd, it can be made even by using 1, 3, 5, 7, or 9for the 6th digit ... 5 choices.-- If the sum of the first 5 digits is even, it remains even by using 2, 4, 6, 8, or 0for the 6th digit ... 5 choices.-- So, for any one of the 90,000 five-digit numbers, there are 5 choices for the 6th digitthat result in an even sum of all six.-- So, there must be 450,000 suitable 6-digit numbers.
100000000*first digit+10000000*second digit+1000000*third digit+100000*fourth digit+10000*fifth digit+1000*sixth digit+100*seventh digit+10*eightth digit+1*nineth digit
I am a four digit number. My tens digit is 2 more than my ones digit. My hundreds and thousands digit are both 1 less than my ones digit. What number can i be?
421 and 842
one
The 6th digit indicates the year
0 - There are no 0s in pi 1 - 2nd digit 2 - 7th digit 3 - 1st digit 4 - 3rd digit 5 - 5th digit 6 - 8th digit 7 - 14th digit 8 - 12th digit 9 - 6th digit
First digit is Divisional code Next 4 are Body style code The 6th digit is Model year The 7th digit is the Plant code The last 6 are the Unit number
1 million = 1,000,000 → 17914351 = 17914351 ÷ 1,000,000 million = 17.914351 million To the nearest tenth of a million this is rounded using the hundredth of a million to decide whether to round up or down. The hundredth of a million digit is 1, so sound down → 17.914351 million → 17.9 million to the nearest tenth of a million → 17.9 million = 17.9 × 1,000,000 = 17,900,000 Alternatively: Tenth of a million = 1/10 × 1,000,000 = 100,000 → Rounding to the nearest tenth of a million is rounding to the nearest 100,000 (hundred thousand) The hundred thousand digit is the 6th digit from the right hand end (of a whole number), so the ten thousand digit (the 5th digit from the right hand end) is the deciding digit. Round the 6th digit based on the 5th digit and then replace all the digits to the right of the 6th digit by zeros. The 5th from the end is '1', so round down → 17914351 → 17900000 to the nearest tenth of a million.
Either the 6th, 12th, or 13th depending on your 9 digit zip code.
I look at it this way:-- There are 90,000 numbers with five digits. (100,000 minus 10,000 with less than 5 digits)-- If the sum of the first 5 digits is odd, it can be made even by using 1, 3, 5, 7, or 9for the 6th digit ... 5 choices.-- If the sum of the first 5 digits is even, it remains even by using 2, 4, 6, 8, or 0for the 6th digit ... 5 choices.-- So, for any one of the 90,000 five-digit numbers, there are 5 choices for the 6th digitthat result in an even sum of all six.-- So, there must be 450,000 suitable 6-digit numbers.
2 ÷ 7 = 0.285714285714... ie it repeats the 6 digits: {2, 8, 5, 7, 1, 4}. Therefore taking the digit place modulus 6 will tell you which of these digits occupies that position (if the result of the modulus is 0, the 6th of the list, ie the '4', is the required digit). 1001 mod 6 = 5 → 1001st digit of 2/7 is a '1' (assuming the 1st digit is the 1st digit after the decimal point).
There are a few different options for the Accord. They are as follows: 3.0L (6 cyl, VIN "1" & "2" 6th digit) 2.3L (4 cyl), EX (VTEC, VIN "3", "5" or "6" 6th digit), w/o ULEV 2.3L (4 cyl), EX (VTEC, VIN "3", "5" or "6" 6th digit), w/ULEV 2.3L (4 cyl), DX (VIN "8" 6th digit) 2.3L (4 cyl), LX (VTEC, VIN "3", "5" or "6" 6th digit), w/o ULEV 2.3L (4 cyl), LX (VTEC, VIN "3", "5" or "6" 6th digit), w/ULEV As long as the VIN (looks like the 6th digit in this case), and engine size matches in the cars your swapping to and from and they both either have ULEV or both don't have ULEV then you should be able to swap motors without a problem. And I'm pretty sure the LX and EX motors are compatibale because they're the same motor, you just might have to swap a few parts from your old motor to the new one, like maybe motor mounts, possibly a few senors. Pretty much anything that looks diffrent between the motors. If a connector doesn't connect to the harness then the sensor will have to be moved from the old connector to the new connector. And one last thing, if the cars have different transmissions (automatic vs. manual) then you will have to swap the throttle body as well.
100000000*first digit+10000000*second digit+1000000*third digit+100000*fourth digit+10000*fifth digit+1000*sixth digit+100*seventh digit+10*eightth digit+1*nineth digit
the unit digit is the last digit from left or ones digit
4284
4082 Since the tens digit is 2 times the thousand digit, it must be an even digit. So it can be 8, 6, 4, or 2. But, the thousands digit is 4 greater than the hundred digit. So that the hundred digit must be 0, the thousands digit must be 4, the hundreds digit must be 8, and the ones digit must be 2.