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100000000*first digit+10000000*second digit+1000000*third digit+100000*fourth digit+10000*fifth digit+1000*sixth digit+100*seventh digit+10*eightth digit+1*nineth digit

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Q: How do you expand 9 digit numbers?
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Related questions

What are the most frequent 3 digit numbers between 0 to 9?

There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.


How many 4 digit numbers have 6 as their second digit?

There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.


How many different three digit numbers can be written using the digits 1 through 9?

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.


How many numbers are there between 100 and 999 in which all three digit numbers are different?

There are 9 possible numbers for the first digit (one of {1, 2, ..., 9}); with 9 possible digits for the second digit (one of {0, 1, 2, ..., 9} which is not the first digit)); with 8 possible digits for the third digit (one of {0, 1, 2, ..., 9} less the 2 digits already chosen); This there are 9 × 9 × 8 = 648 such numbers.


How many 4 digit numbers are possible by 9 and 6?

There are 16 4-digit numbers that can be made up from 9 and 6.


How many 4 digit numbers contain the digit 5?

There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.


How many 3 digit numbers can be made with numbers 1 - 9?

999-111=888 888 3 digit numbers can be made with numbers between 1 - 9


How many 3 digit numbers contain the digit 8?

-5


How many thousands are there in Ten Thousands?

There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers


How many 2-digit numbers contain the digit?

It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.


How many 9 digit numbers are there?

well the first 9 digit number is 100 million 100,000,000 the last 9 digit number is 999 million 999,999,999 just minus the two numbers and you get... 899,999,999 so there are around 900 million 9 digit numbers.


What are the different combinations of three digit numbers using 0-9?

9