The sequence given is an arithmetic sequence where the first term is -29 and the common difference is 8 (calculated as -21 - (-29)). To find the 7th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ). Substituting ( a_1 = -29 ), ( d = 8 ), and ( n = 7 ), we get ( a_7 = -29 + (7-1) \cdot 8 = -29 + 48 = 19 ). Thus, the 7th term is 19.
The sequence 5, 13, 21, 29 increases by 8 each time. To find the next term, you add 8 to the last term (29), resulting in 37. Thus, the rule for the sequence is to start at 5 and add 8 for each subsequent term.
It is increasing by 4 and the nth term is 4n+1
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
13 + 26 + 34 + 21 + 38 + 42 = 174/6 = 29
29
nth term = 5 +8n
It is increasing by 4 and the nth term is 4n+1
7917
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
13 + 26 + 34 + 21 + 38 + 42 = 174/6 = 29
It is: 21 because it has more than two factors
PRIME
35
2n +29
21 as all other are prime no. except 21 which is a multiple of 3 and 7
29
Arithmetic