2n +29
It is: 27-2n
It is 4n -1 and so the next term will be 23
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 27-2n
23-2nthis guy has a great way of explaining it, so look at his...What_is_the_nth_term_for_3_7_11_15_19
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
It is 4n -1 and so the next term will be 23
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
If you meant: 2 12 22 32 then the nth term = 10n-8
21 is composite. 19 and 23 are prime.
To find the nth term of the sequence 6, 21, 44, 75, 114, we can look for a pattern in the differences between the terms. The first differences are 15, 23, 31, and 39, which increase by 8 each time. This suggests a quadratic relationship, so we can express the nth term as a quadratic function: ( a_n = An^2 + Bn + C ). By solving for A, B, and C using the first few terms, we find the nth term is given by ( a_n = 4n^2 + 2n ).
9 ,16 ,23, 30 We note that there is a difference of '7' between terms. So the first part of the 'nth' term is 7n. Note the '7' becomes multiple. Next we need to find the constant 'c' So taking the first term (n = 1) we write. 7n + c = 9 7(1) + c = 9 7 + c = 9 c = 2 So the 'nth' term is '7n + 2' To verify , try the 3rd term n= 3 then answer should be '23'. 7(3) + 2 = 21 + 2 = 23 As required.
14+9n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].