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If the circle and x-axis are tangential then the centre of the circle must be at a distance equal to the radius away from the x-axis. That is, the centre of the circle must lie on y = ±r (where r = radius) so that the coordinates of the centre are (a, ±r)

So the equation of the set of circles is

(x - a)2 + (y ± r)2 = r2

Differentiating gives

2*(x - a) + 2*(y ± r)*dy/dx = 0

(x - a) + (y ± r)*dy/dx = 0

so that

dy/dx = (a - x)/(y ± r)

It is not clear why you would want the differential equation, but you asked for it so you've got it!

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Q: What is the Differential equation of circles tangent to x-axis with solution?
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