GCD: 1
GCD: 13
Divide the larger number by the smaller one and then replace the larger by the remainder. Repeat until a remainder is 0 or both numbers are 1. In the first case, the non-zero number is the GCD, in the other case, the numbers are coprme: GCD = 1. Thus GCD(85, 102) 102 = 1*85 + R = 17 so GCD(85, 17) 85 = 5*17 + R = 0 so GCD(0, 17) therefore 17. = GCD[85, (102-85)] = GCD(85, 17)
17 + 14 + 17 + 19 + 18 + 13 + 11 = 109
11+13+17+19= 60ANSWER: 60
1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19.
GCD: 13
GCD: 1
The Greatest Common Divisor (GCD) for 17 24 is 1.
11, 13, 17, 19
To simplify the fraction 17/19 to its lowest terms, we need to find the greatest common divisor (GCD) of 17 and 19, which is 1 since 17 and 19 are prime numbers and have no common factors other than 1. Therefore, the fraction 17/19 is already in its simplest form and cannot be further reduced.
13, 15, 17, 19
11, 13, 17, 19 and 2311, 13, 17, 19, 23
3, 5, 7, 11, 13, 17, 19, 23, 293, 5, 7, 11, 13, 17, 19, 23, 293, 5, 7, 11, 13, 17, 19, 23, 293, 5, 7, 11, 13, 17, 19, 23, 29
The prime numbers after ten are: 11 13 17 19 23 29
2 5 9 10 13 17 19
Divide the larger number by the smaller one and then replace the larger by the remainder. Repeat until a remainder is 0 or both numbers are 1. In the first case, the non-zero number is the GCD, in the other case, the numbers are coprme: GCD = 1. Thus GCD(85, 102) 102 = 1*85 + R = 17 so GCD(85, 17) 85 = 5*17 + R = 0 so GCD(0, 17) therefore 17. = GCD[85, (102-85)] = GCD(85, 17)
19