Factors of 91: 1, 7, 13, 91Factors of 117: 1, 3, 9, 13, 39, 117GCF (91, 117) = 13
For 117, 91, 65, 21 the LCM is: 4,095
The GCF is 13.
117/91(divide both sides by 13)9/7
1 and 13
It is 100*(117 - 91)/117 = 22.2 Recurring) %
This is my method to find GCD of 2 big numbers A and B and expressing that gcd of the form mA + nBFirst, let us find the gcd. Let us call it as d1) Divide the bigger number by the smaller one.2) Divide the smaller number by the remainder u get in step 1.3) Divide the step 1 remainder by step 2, then each remainder by the next remainder and so on.4) Reach the step when u get no remainder at all. The divisor will be the LCM.Let me explain it with an example.Q. Find the gcd of 858 and 325 and express it in the form of m858 + n325.Solution :858 = 325*2 + 208325 = 208*1 + 117208 = 117*1 + 91117 = 91*1 + 2691 = 26*3 + 1326 = 13.2thr4, gcd 0f 858 and 325 is d = 13d = 13 = 91 - 26*3= 91 -3(117 - 91*1)= 91*4 - 117*3=4(208-117) - 117*3= 4*208 - 7*117= 4*208 - 7(325-208)=11*208 -7*325=11*(858-325*2) - 7*325=11*858 - 29*325thr4, d = 13 = m*858 + n*325 where m =11 and n = -29
Factors of 91: 1, 7, 13, 91Factors of 117: 1, 3, 9, 13, 39, 117GCF (91, 117) = 13
It is: 728
For 117, 91, 65, 21 the LCM is: 4,095
The GCF is 13.
26 + 91 = 117
The GCF is 13.
117/91(divide both sides by 13)9/7
The greatest common denominator (gcd) of 42 and 117 is 3. So 3 is the only factor of both.
Oh, dude, like, the least common multiple (LCM) for 26, 91, and 117 is 2366. It's like the smallest number that all three of those numbers can divide into evenly without leaving a remainder. So, yeah, that's the LCM for those three numbers.
The answer is: 1