55/5ab + 4/5ab = 59/5ab
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
98
35ab squared
GCD(125, 225) = 25 GCD(125, 225) = 25 GCD(125, 225) = 25 GCD(125, 225) = 25
55/5ab + 4/5ab = 59/5ab
Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.
7ab-5ab = 2
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
2x2 + 28xy + 98y2 = 2(x + 7)2.
(5ab^2 + 4cd)(5ab^2 4cd) <
(5ab)2 = 25a2b2 (provided a and b are elements of a commutative group).
The GCF of 5ab and 56b squared is b.
6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab
35ab
1.25