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x3 + 13x2 + 42x = x(x + 6)(x + 7).
no. it can be simplified into 13x2. 13 and 2 are prime.
13x1=13 13x2=26...etc
x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)
5x2 + 3x + 8x2 = 13x2 + 3x = x(13x + 3)